poetry critical

online poetry workshop

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Welcome!

Welcome to Poetry Critical, an online poetry workshop. To post your own poetry you'll need to create a user id by typing a name and password in the box above and hitting 'New User'. If you just want to critique or jump into the discussion, however, you can go ahead and get started!

Poetry Critical 2.0

Hey guys, Donald here.

In a few weeks, this site will be 9 years old. 9 years! And I still know some of the earliest submissions by heart.

But, boy. That’s like 102 in web-years. So it’s time for something new. I’m building that something now with my nights-and-weekend minutes (and plenty of coffee). Buy me a cup?

Development updates from Twitter:

Follow @poetrycritical for more!

Random Poem:

Zero
unknown

"Smart is sexy, but not your kind of smart," she said.
 1
I nodded.
 2
"Excessive intelligence is just repulsive," she deduced.
 3
"Correct," I said.
 4
"If you were a number, you'd be a zero," she added.
 5
Again I concurred.
 6
She never called me back. I don't blame her.
 7
She's too smart for that.
 8
 
 
So, tonight I am attempting to prove the Goldbach conjecture
 9
or find the six billionth digit of pi in base 23.
 10
 
 
log_2n 1944 = log_n (486 √2)
 11
=> log_2 1944 / log_2 (2n) = log_2 (486 √2) / log_2 n
 12
=> log_2 1944 / (1 + log_2 n) = (log_2 486 + 1/2) / log_2 n
 13
=> log_2 1944 log_2 n = (log_2 486 + 1/2) (log_2 n + 1)
 14
=> (log_2 1944 - log_2 486 - 1/2) log_2 n = log_2 486 + 1/2
 15
=> (log_2 4 - 1/2) log_2 n = log_2 486 + 1/2
 16
=> log_2 n = 2/3 log_2 486 + 1/3
 17
=> log_2 n^6 = 6 log_2 n = 4 log_2 486 + 2
 18
=> n^6 = 486^4 . 2^2
 19
= 2^6 . 3^20
 20
= 223154201664.
 21
 
 
By midnight I had worked out a partial solution
 22
which enabled me to trace my error in log 486 + 1.2;
 23
this should be:
 24
 
 
4(r^2 + r - j^3) = -28, i.e.
 25
r^2 + r = j^3 - 7, where j must be odd.
 26
This yields a solution for j=3, r=4 or -5, corresponding to x=12, y=±36.
 27
But there are no other solutions in this branch with x
 28
≤ 100,004, |y|  2m^2 + 2m = 4k^3 + 6k^2 + 3k - 216
 29
All terms have even coefficient except 3k, so k must be even:
 30
let k = 2j
 31
=> m^2 + m = 16j^3 + 12j^2 + 3j - 108
 32
Since the LHS is always even, 3j must also be even,
 33
so let j = 2r:
 34
=> m^2 + m = 128r^3 + 48r^2 + 6r - 108
 35
Now m^2 + m = (m+1/2)^2 - 1/4 will always be non-negative
 36
for integer m, and the sign of the RHS
 37
will be dominated by the leading term for r negative,
 38
so r must be positive.
 39
I can also show that r does not have residue 2 mod 3,
 40
but can't get much further at the moment.
 41
There are no (apparent) solutions for
 42
r ≤ 12,500 (x ≤ 100,001; |y| ≤ 31,623,251).
 43
 
 
It may inelegant, but I shall prevail.
 44
 
 
Another quiet evening with some paper and a pencil
 45
and a glass of chocolate milk,
 46
these equations and a sugar high to keep me company.
 47
Math makes sense to me. Women do not.
 48
Problems can be qualified and calculated and eventually corrected.
 49
There are foreseeable solutions to math equations using logic,
 50
formula and a little perseverance.
 51
I know my perimeters with numbers,
 52
but with women I am almost always incorrect in my calculations.
 53
 
 
Women bring confusion and doubt and pain.
 54
And I miss that.
 55
I don't understand it,
 56
but I miss the confusion and doubt and pain.
 57
I miss it dearly.
 58

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